X+5/4x^2+23x+18

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Solution for X+5/4x^2+23x+18 equation: 


x in (-oo:+oo)

X+(5/4)*x^2+23*x+18 = 0

X+5/4*x^2+23*x+18 = 0

DELTA = 23^2-(5/4*4*(X+18))

DELTA = 529-5*(X+18)

529-5*(X+18) = 0

529-5*(X+18) = 0

439-5*X = 0

439-5*X = 0

439-5*X = 0 // - 439

-5*X = -439 // : -5

X = -439/(-5)

X = 439/5

DELTA = 0  <=>  t_1 = 439/5

x = -23/(5/4*2) i X = 439/5

x = -46/5 i X = 439/5

( x = ((529-5*(X+18))^(1/2)-23)/(5/4*2) or x = (-(529-5*(X+18))^(1/2)-23)/(5/4*2) ) i X > 439/5

( x = 2/5*((529-5*(X+18))^(1/2)-23) or x = -2/5*((529-5*(X+18))^(1/2)+23) ) i X > 439/5

X-439/5 > 0

X-439/5 > 0 // + 439/5

X > 439/5

x in { -46/5, 2/5*((529-5*(X+18))^(1/2)-23), -2/5*((529-5*(X+18))^(1/2)+23) }

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